Base | Representation |
---|---|
bin | 110001001001111101… |
… | …010000101001100111 |
3 | 12001020100122021220222 |
4 | 301021331100221213 |
5 | 1331043240401203 |
6 | 40125203114555 |
7 | 3545643011555 |
oct | 611175205147 |
9 | 161210567828 |
10 | 52780403303 |
11 | 20425186221 |
12 | a290072a5b |
13 | 4c91ac8294 |
14 | 27a9ad2bd5 |
15 | 158da0d038 |
hex | c49f50a67 |
52780403303 has 4 divisors (see below), whose sum is σ = 54600417240. Its totient is φ = 50960389368.
The previous prime is 52780403261. The next prime is 52780403311. The reversal of 52780403303 is 30330408725.
52780403303 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 52780403303 - 26 = 52780403239 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (52780403323) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 910006925 + ... + 910006982.
It is an arithmetic number, because the mean of its divisors is an integer number (13650104310).
Almost surely, 252780403303 is an apocalyptic number.
52780403303 is a deficient number, since it is larger than the sum of its proper divisors (1820013937).
52780403303 is a wasteful number, since it uses less digits than its factorization.
52780403303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1820013936.
The product of its (nonzero) digits is 60480, while the sum is 35.
The spelling of 52780403303 in words is "fifty-two billion, seven hundred eighty million, four hundred three thousand, three hundred three".
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