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528325113 = 3176108371
BaseRepresentation
bin11111011111011…
…001100111111001
31100211010200210210
4133133121213321
52040222400423
6124231501333
716043455311
oct3737314771
91324120723
10528325113
11251253528
12128b27849
13855c1914
145024a441
15315b0b93
hex1f7d99f9

528325113 has 4 divisors (see below), whose sum is σ = 704433488. Its totient is φ = 352216740.

The previous prime is 528325097. The next prime is 528325177. The reversal of 528325113 is 311523825.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 528325113 - 24 = 528325097 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (528325013) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 88054183 + ... + 88054188.

It is an arithmetic number, because the mean of its divisors is an integer number (176108372).

Almost surely, 2528325113 is an apocalyptic number.

It is an amenable number.

528325113 is a deficient number, since it is larger than the sum of its proper divisors (176108375).

528325113 is a wasteful number, since it uses less digits than its factorization.

528325113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 176108374.

The product of its digits is 7200, while the sum is 30.

The square root of 528325113 is about 22985.3238611075. The cubic root of 528325113 is about 808.4138614593.

Adding to 528325113 its reverse (311523825), we get a palindrome (839848938).

The spelling of 528325113 in words is "five hundred twenty-eight million, three hundred twenty-five thousand, one hundred thirteen".

Divisors: 1 3 176108371 528325113