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5288806010753 is a prime number
BaseRepresentation
bin100110011110110010101…
…1001110100111110000001
3200201121022222120120200222
41030331211121310332001
51143122433314321003
615125351031352425
71054050354230366
oct114754531647601
920647288516628
105288806010753
111759a74128a81
1271500a522715
132c4969a370a5
14143d9dd5c46d
15928922c2c38
hex4cf65674f81

5288806010753 has 2 divisors, whose sum is σ = 5288806010754. Its totient is φ = 5288806010752.

The previous prime is 5288806010749. The next prime is 5288806010771. The reversal of 5288806010753 is 3570106088825.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3725235827569 + 1563570183184 = 1930087^2 + 1250428^2 .

It is a cyclic number.

It is not a de Polignac number, because 5288806010753 - 22 = 5288806010749 is a prime.

It is a super-3 number, since 3×52888060107533 (a number of 39 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 5288806010695 and 5288806010704.

It is not a weakly prime, because it can be changed into another prime (5288806010723) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2644403005376 + 2644403005377.

It is an arithmetic number, because the mean of its divisors is an integer number (2644403005377).

Almost surely, 25288806010753 is an apocalyptic number.

It is an amenable number.

5288806010753 is a deficient number, since it is larger than the sum of its proper divisors (1).

5288806010753 is an equidigital number, since it uses as much as digits as its factorization.

5288806010753 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3225600, while the sum is 53.

The spelling of 5288806010753 in words is "five trillion, two hundred eighty-eight billion, eight hundred six million, ten thousand, seven hundred fifty-three".