Base | Representation |
---|---|
bin | 110001010010111111… |
… | …011110011000010101 |
3 | 12001121220212010101021 |
4 | 301102333132120111 |
5 | 1331401041310043 |
6 | 40152220001141 |
7 | 3552463252552 |
oct | 612277363025 |
9 | 161556763337 |
10 | 52931978773 |
11 | 204a27a4103 |
12 | a3129901b1 |
13 | 4cb73292cb |
14 | 27c1caba29 |
15 | 159be9e3ed |
hex | c52fde615 |
52931978773 has 2 divisors, whose sum is σ = 52931978774. Its totient is φ = 52931978772.
The previous prime is 52931978741. The next prime is 52931978779. The reversal of 52931978773 is 37787913925.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 34715887684 + 18216091089 = 186322^2 + 134967^2 .
It is a cyclic number.
It is not a de Polignac number, because 52931978773 - 25 = 52931978741 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (52931978779) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26465989386 + 26465989387.
It is an arithmetic number, because the mean of its divisors is an integer number (26465989387).
Almost surely, 252931978773 is an apocalyptic number.
It is an amenable number.
52931978773 is a deficient number, since it is larger than the sum of its proper divisors (1).
52931978773 is an equidigital number, since it uses as much as digits as its factorization.
52931978773 is an evil number, because the sum of its binary digits is even.
The product of its digits is 20003760, while the sum is 61.
The spelling of 52931978773 in words is "fifty-two billion, nine hundred thirty-one million, nine hundred seventy-eight thousand, seven hundred seventy-three".
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