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52951000931 is a prime number
BaseRepresentation
bin110001010100001000…
…000010011101100011
312001200020122112212122
4301110020002131203
51331420424012211
640154135414455
73553114040003
oct612410023543
9161606575778
1052951000931
11205025067a4
12a31922442b
134cbb25961a
1427c4620003
15159d9aa6db
hexc54202763

52951000931 has 2 divisors, whose sum is σ = 52951000932. Its totient is φ = 52951000930.

The previous prime is 52951000909. The next prime is 52951000933. The reversal of 52951000931 is 13900015925.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 52951000931 - 218 = 52950738787 is a prime.

It is a super-2 number, since 2×529510009312 (a number of 22 digits) contains 22 as substring.

Together with 52951000933, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 52951000891 and 52951000900.

It is not a weakly prime, because it can be changed into another prime (52951000933) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26475500465 + 26475500466.

It is an arithmetic number, because the mean of its divisors is an integer number (26475500466).

Almost surely, 252951000931 is an apocalyptic number.

52951000931 is a deficient number, since it is larger than the sum of its proper divisors (1).

52951000931 is an equidigital number, since it uses as much as digits as its factorization.

52951000931 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12150, while the sum is 35.

The spelling of 52951000931 in words is "fifty-two billion, nine hundred fifty-one million, nine hundred thirty-one", and thus it is an aban number.