Base | Representation |
---|---|
bin | 100110100100000000010… |
… | …1001100111011101100111 |
3 | 200202200020011002020110122 |
4 | 1031020000221213131213 |
5 | 1143313400120142212 |
6 | 15134441525312155 |
7 | 1054624645246262 |
oct | 115100051473547 |
9 | 20680204066418 |
10 | 5300000552807 |
11 | 1763799161124 |
12 | 71721356565b |
13 | 2c5a3205767c |
14 | 1447429cdcd9 |
15 | 92ce9e8e272 |
hex | 4d200a67767 |
5300000552807 has 2 divisors, whose sum is σ = 5300000552808. Its totient is φ = 5300000552806.
The previous prime is 5300000552713. The next prime is 5300000552857. The reversal of 5300000552807 is 7082550000035.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5300000552807 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5300000552857) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2650000276403 + 2650000276404.
It is an arithmetic number, because the mean of its divisors is an integer number (2650000276404).
Almost surely, 25300000552807 is an apocalyptic number.
5300000552807 is a deficient number, since it is larger than the sum of its proper divisors (1).
5300000552807 is an equidigital number, since it uses as much as digits as its factorization.
5300000552807 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 42000, while the sum is 35.
The spelling of 5300000552807 in words is "five trillion, three hundred billion, five hundred fifty-two thousand, eight hundred seven".
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