Base | Representation |
---|---|
bin | 110001010111000100… |
… | …001100101000100111 |
3 | 12001210200110111200212 |
4 | 301113010030220213 |
5 | 1332021040410141 |
6 | 40203100530035 |
7 | 3554253222626 |
oct | 612704145047 |
9 | 161720414625 |
10 | 53000325671 |
11 | 20528336147 |
12 | a33185091b |
13 | 4cc8539567 |
14 | 27cadbd6bd |
15 | 15a2ea02eb |
hex | c5710ca27 |
53000325671 has 2 divisors, whose sum is σ = 53000325672. Its totient is φ = 53000325670.
The previous prime is 53000325661. The next prime is 53000325787. The reversal of 53000325671 is 17652300035.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 53000325671 - 26 = 53000325607 is a prime.
It is a super-3 number, since 3×530003256713 (a number of 33 digits) contains 333 as substring.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53000325611) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26500162835 + 26500162836.
It is an arithmetic number, because the mean of its divisors is an integer number (26500162836).
Almost surely, 253000325671 is an apocalyptic number.
53000325671 is a deficient number, since it is larger than the sum of its proper divisors (1).
53000325671 is an equidigital number, since it uses as much as digits as its factorization.
53000325671 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18900, while the sum is 32.
The spelling of 53000325671 in words is "fifty-three billion, three hundred twenty-five thousand, six hundred seventy-one".
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