Base | Representation |
---|---|
bin | 110001010111000100… |
… | …111001101000000101 |
3 | 12001210200210212111021 |
4 | 301113010321220011 |
5 | 1332021112304312 |
6 | 40203104511141 |
7 | 3554254621123 |
oct | 612704715005 |
9 | 161720725437 |
10 | 53000509957 |
11 | 2052845164a |
12 | a33191b4b1 |
13 | 4cc85a23c5 |
14 | 27cb02a913 |
15 | 15a2ed9c07 |
hex | c57139a05 |
53000509957 has 8 divisors (see below), whose sum is σ = 54532718240. Its totient is φ = 51481921680.
The previous prime is 53000509943. The next prime is 53000509981. The reversal of 53000509957 is 75990500035.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 53000509957 - 27 = 53000509829 is a prime.
It is a super-2 number, since 2×530005099572 (a number of 22 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (43).
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53000509927) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3397107 + ... + 3412672.
It is an arithmetic number, because the mean of its divisors is an integer number (6816589780).
Almost surely, 253000509957 is an apocalyptic number.
It is an amenable number.
53000509957 is a deficient number, since it is larger than the sum of its proper divisors (1532208283).
53000509957 is a wasteful number, since it uses less digits than its factorization.
53000509957 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6810003.
The product of its (nonzero) digits is 212625, while the sum is 43.
The spelling of 53000509957 in words is "fifty-three billion, five hundred nine thousand, nine hundred fifty-seven".
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