Base | Representation |
---|---|
bin | 100110100100000001111… |
… | …0001110110110100011111 |
3 | 200202200100210212002112211 |
4 | 1031020003301312310133 |
5 | 1143314002034411021 |
6 | 15134451042341251 |
7 | 1054626153362311 |
oct | 115100361666437 |
9 | 20680323762484 |
10 | 5300053044511 |
11 | 17638158539a5 |
12 | 71722905a827 |
13 | 2c5a3cba5c54 |
14 | 1447499757b1 |
15 | 92cee8ac3e1 |
hex | 4d203c76d1f |
5300053044511 has 2 divisors, whose sum is σ = 5300053044512. Its totient is φ = 5300053044510.
The previous prime is 5300053044469. The next prime is 5300053044529. The reversal of 5300053044511 is 1154403500035.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5300053044511 - 27 = 5300053044383 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5300053044551) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2650026522255 + 2650026522256.
It is an arithmetic number, because the mean of its divisors is an integer number (2650026522256).
Almost surely, 25300053044511 is an apocalyptic number.
5300053044511 is a deficient number, since it is larger than the sum of its proper divisors (1).
5300053044511 is an equidigital number, since it uses as much as digits as its factorization.
5300053044511 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18000, while the sum is 31.
Adding to 5300053044511 its reverse (1154403500035), we get a palindrome (6454456544546).
The spelling of 5300053044511 in words is "five trillion, three hundred billion, fifty-three million, forty-four thousand, five hundred eleven".
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