Base | Representation |
---|---|
bin | 1001110111110100… |
… | …00110010011010111 |
3 | 111200100222121011221 |
4 | 10323322012103113 |
5 | 41323303200312 |
6 | 2233530311211 |
7 | 245224465111 |
oct | 47372062327 |
9 | 14610877157 |
10 | 5300053207 |
11 | 227a818469 |
12 | 103ab88507 |
13 | 666077977 |
14 | 383c8a3b1 |
15 | 210476207 |
hex | 13be864d7 |
5300053207 has 2 divisors, whose sum is σ = 5300053208. Its totient is φ = 5300053206.
The previous prime is 5300053163. The next prime is 5300053247. The reversal of 5300053207 is 7023500035.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5300053207 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5300053247) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2650026603 + 2650026604.
It is an arithmetic number, because the mean of its divisors is an integer number (2650026604).
Almost surely, 25300053207 is an apocalyptic number.
5300053207 is a deficient number, since it is larger than the sum of its proper divisors (1).
5300053207 is an equidigital number, since it uses as much as digits as its factorization.
5300053207 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3150, while the sum is 25.
The square root of 5300053207 is about 72801.4643190644. The cubic root of 5300053207 is about 1743.5192356555.
The spelling of 5300053207 in words is "five billion, three hundred million, fifty-three thousand, two hundred seven".
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