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530006051773241 is a prime number
BaseRepresentation
bin111100010000010011010011…
…0011100011101101100111001
32120111121002021000202100010022
41320200212212130131230321
51023432104343223220431
65115121230251300225
7216431450021643641
oct17040464634355471
92514532230670108
10530006051773241
11143970338aa670a
124b53a88244a675
1319997482828244
1494c4603451521
154141a18b3a07b
hex1e209a671db39

530006051773241 has 2 divisors, whose sum is σ = 530006051773242. Its totient is φ = 530006051773240.

The previous prime is 530006051773207. The next prime is 530006051773243. The reversal of 530006051773241 is 142377150600035.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 387404742760000 + 142601309013241 = 19682600^2 + 11941579^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-530006051773241 is a prime.

Together with 530006051773243, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 530006051773192 and 530006051773201.

It is not a weakly prime, because it can be changed into another prime (530006051773243) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265003025886620 + 265003025886621.

It is an arithmetic number, because the mean of its divisors is an integer number (265003025886621).

Almost surely, 2530006051773241 is an apocalyptic number.

It is an amenable number.

530006051773241 is a deficient number, since it is larger than the sum of its proper divisors (1).

530006051773241 is an equidigital number, since it uses as much as digits as its factorization.

530006051773241 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 529200, while the sum is 44.

The spelling of 530006051773241 in words is "five hundred thirty trillion, six billion, fifty-one million, seven hundred seventy-three thousand, two hundred forty-one".