Base | Representation |
---|---|
bin | 110001010111000110… |
… | …001111010010110010 |
3 | 12001210201110200211022 |
4 | 301113012033102302 |
5 | 1332021210021400 |
6 | 40203120215442 |
7 | 3554260612130 |
oct | 612706172262 |
9 | 161721420738 |
10 | 53000860850 |
11 | 20528671243 |
12 | a331a6a582 |
13 | 4cc8696032 |
14 | 27cb0bc750 |
15 | 15a3058b85 |
hex | c5718f4b2 |
53000860850 has 48 divisors (see below), whose sum is σ = 112890840000. Its totient is φ = 18135247680.
The previous prime is 53000860841. The next prime is 53000860873. The reversal of 53000860850 is 5806800035.
53000860850 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a Harshad number since it is a multiple of its sum of digits (35).
It is a self number, because there is not a number n which added to its sum of digits gives 53000860850.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 22916 + ... + 326384.
It is an arithmetic number, because the mean of its divisors is an integer number (2351892500).
Almost surely, 253000860850 is an apocalyptic number.
53000860850 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
53000860850 is an abundant number, since it is smaller than the sum of its proper divisors (59889979150).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
53000860850 is a wasteful number, since it uses less digits than its factorization.
53000860850 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 303987 (or 303982 counting only the distinct ones).
The product of its (nonzero) digits is 28800, while the sum is 35.
The spelling of 53000860850 in words is "fifty-three billion, eight hundred sixty thousand, eight hundred fifty".
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