Base | Representation |
---|---|
bin | 11000000110100010011111… |
… | …00110110101010000100111 |
3 | 20221122212102222200020210011 |
4 | 30003101033212311100213 |
5 | 23421333010343343302 |
6 | 304420232503111051 |
7 | 14110132636542664 |
oct | 1403211746652047 |
9 | 227585388606704 |
10 | 53001232012327 |
11 | 15984772805975 |
12 | 5b3bbb1442487 |
13 | 2375cc1575251 |
14 | d133b7da4a6b |
15 | 61da3c6145d7 |
hex | 30344f9b5427 |
53001232012327 has 2 divisors, whose sum is σ = 53001232012328. Its totient is φ = 53001232012326.
The previous prime is 53001232012247. The next prime is 53001232012361. The reversal of 53001232012327 is 72321023210035.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 53001232012327 - 27 = 53001232012199 is a prime.
It is a super-3 number, since 3×530012320123273 (a number of 42 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53001232012367) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26500616006163 + 26500616006164.
It is an arithmetic number, because the mean of its divisors is an integer number (26500616006164).
Almost surely, 253001232012327 is an apocalyptic number.
53001232012327 is a deficient number, since it is larger than the sum of its proper divisors (1).
53001232012327 is an equidigital number, since it uses as much as digits as its factorization.
53001232012327 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15120, while the sum is 31.
The spelling of 53001232012327 in words is "fifty-three trillion, one billion, two hundred thirty-two million, twelve thousand, three hundred twenty-seven".
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