Base | Representation |
---|---|
bin | 110001010111001000… |
… | …011000001000010011 |
3 | 12001210202112011122212 |
4 | 301113020120020103 |
5 | 1332021330440311 |
6 | 40203140222335 |
7 | 3554265435155 |
oct | 612710301023 |
9 | 161722464585 |
10 | 53001421331 |
11 | 20528a14351 |
12 | a33209a9ab |
13 | 4cc8831191 |
14 | 27cb1c6ad5 |
15 | 15a3119c8b |
hex | c57218213 |
53001421331 has 2 divisors, whose sum is σ = 53001421332. Its totient is φ = 53001421330.
The previous prime is 53001421309. The next prime is 53001421349. The reversal of 53001421331 is 13312410035.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 53001421331 - 222 = 52997227027 is a prime.
It is a super-2 number, since 2×530014213312 (a number of 22 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is a junction number, because it is equal to n+sod(n) for n = 53001421297 and 53001421306.
It is not a weakly prime, because it can be changed into another prime (53001421391) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26500710665 + 26500710666.
It is an arithmetic number, because the mean of its divisors is an integer number (26500710666).
Almost surely, 253001421331 is an apocalyptic number.
53001421331 is a deficient number, since it is larger than the sum of its proper divisors (1).
53001421331 is an equidigital number, since it uses as much as digits as its factorization.
53001421331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1080, while the sum is 23.
Adding to 53001421331 its reverse (13312410035), we get a palindrome (66313831366).
The spelling of 53001421331 in words is "fifty-three billion, one million, four hundred twenty-one thousand, three hundred thirty-one".
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