Base | Representation |
---|---|
bin | 1111011011001111011… |
… | …10001000000101101101 |
3 | 1212200002002020202010020 |
4 | 13231213232020011231 |
5 | 32140440401404123 |
6 | 1043253252032353 |
7 | 53202263130516 |
oct | 7554756100555 |
9 | 1780062222106 |
10 | 530021122413 |
11 | 194865119072 |
12 | 8687b0026b9 |
13 | 3ac999ca133 |
14 | 1b9203a9a0d |
15 | dbc15307e3 |
hex | 7b67b8816d |
530021122413 has 4 divisors (see below), whose sum is σ = 706694829888. Its totient is φ = 353347414940.
The previous prime is 530021122361. The next prime is 530021122447. The reversal of 530021122413 is 314221120035.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 530021122413 - 214 = 530021106029 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (530021122313) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 88336853733 + ... + 88336853738.
It is an arithmetic number, because the mean of its divisors is an integer number (176673707472).
Almost surely, 2530021122413 is an apocalyptic number.
It is an amenable number.
530021122413 is a deficient number, since it is larger than the sum of its proper divisors (176673707475).
530021122413 is a wasteful number, since it uses less digits than its factorization.
530021122413 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 176673707474.
The product of its (nonzero) digits is 1440, while the sum is 24.
Adding to 530021122413 its reverse (314221120035), we get a palindrome (844242242448).
The spelling of 530021122413 in words is "five hundred thirty billion, twenty-one million, one hundred twenty-two thousand, four hundred thirteen".
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