Base | Representation |
---|---|
bin | 110001010111001011… |
… | …000101001100101101 |
3 | 12001210210212012002001 |
4 | 301113023011030231 |
5 | 1332022021131341 |
6 | 40203203332301 |
7 | 3554304446665 |
oct | 612713051455 |
9 | 161723765061 |
10 | 53002130221 |
11 | 20529358a07 |
12 | a332381091 |
13 | 4cc8a1ba41 |
14 | 27cb32d1a5 |
15 | 15a3209d31 |
hex | c572c532d |
53002130221 has 2 divisors, whose sum is σ = 53002130222. Its totient is φ = 53002130220.
The previous prime is 53002130201. The next prime is 53002130243. The reversal of 53002130221 is 12203120035.
53002130221 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 50990607721 + 2011522500 = 225811^2 + 44850^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-53002130221 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53002130201) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26501065110 + 26501065111.
It is an arithmetic number, because the mean of its divisors is an integer number (26501065111).
Almost surely, 253002130221 is an apocalyptic number.
It is an amenable number.
53002130221 is a deficient number, since it is larger than the sum of its proper divisors (1).
53002130221 is an equidigital number, since it uses as much as digits as its factorization.
53002130221 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 360, while the sum is 19.
Adding to 53002130221 its reverse (12203120035), we get a palindrome (65205250256).
The spelling of 53002130221 in words is "fifty-three billion, two million, one hundred thirty thousand, two hundred twenty-one".
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