Base | Representation |
---|---|
bin | 11000000110100100101010… |
… | …01111111101000011000011 |
3 | 20221122222110102020111211201 |
4 | 30003102111033331003003 |
5 | 23421342404001420120 |
6 | 304420544442122031 |
7 | 14110203615051313 |
oct | 1403222517750303 |
9 | 227588412214751 |
10 | 53002400420035 |
11 | 159852122a3980 |
12 | 5b402787b0317 |
13 | 2376149657a61 |
14 | d1348922d443 |
15 | 61daa9eae40a |
hex | 3034953fd0c3 |
53002400420035 has 16 divisors (see below), whose sum is σ = 70058600951040. Its totient is φ = 38172955638240.
The previous prime is 53002400420003. The next prime is 53002400420089.
53002400420035 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 53002400420035 - 25 = 53002400420003 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 53002400419985 and 53002400420012.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4678052625 + ... + 4678063954.
It is an arithmetic number, because the mean of its divisors is an integer number (4378662559440).
Almost surely, 253002400420035 is an apocalyptic number.
53002400420035 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
53002400420035 is a deficient number, since it is larger than the sum of its proper divisors (17056200531005).
53002400420035 is a wasteful number, since it uses less digits than its factorization.
53002400420035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9356116698.
The product of its (nonzero) digits is 14400, while the sum is 28.
It can be divided in two parts, 53002400 and 420035, that added together give a palindrome (53422435).
The spelling of 53002400420035 in words is "fifty-three trillion, two billion, four hundred million, four hundred twenty thousand, thirty-five".
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