Base | Representation |
---|---|
bin | 100110100100001000010… |
… | …0000100100001010101111 |
3 | 200202200220200201121211101 |
4 | 1031020100200210022233 |
5 | 1143314421223143341 |
6 | 15134524152103531 |
7 | 1054634355611212 |
oct | 115102040441257 |
9 | 20680820647741 |
10 | 5300266615471 |
11 | 1763915365a23 |
12 | 717288694ba7 |
13 | 2c5a752022b9 |
14 | 14476a08b779 |
15 | 92d134e7831 |
hex | 4d2108242af |
5300266615471 has 2 divisors, whose sum is σ = 5300266615472. Its totient is φ = 5300266615470.
The previous prime is 5300266615439. The next prime is 5300266615507. The reversal of 5300266615471 is 1745166620035.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5300266615471 - 25 = 5300266615439 is a prime.
It is a super-3 number, since 3×53002666154713 (a number of 39 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5300266615421) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2650133307735 + 2650133307736.
It is an arithmetic number, because the mean of its divisors is an integer number (2650133307736).
Almost surely, 25300266615471 is an apocalyptic number.
5300266615471 is a deficient number, since it is larger than the sum of its proper divisors (1).
5300266615471 is an equidigital number, since it uses as much as digits as its factorization.
5300266615471 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 907200, while the sum is 46.
The spelling of 5300266615471 in words is "five trillion, three hundred billion, two hundred sixty-six million, six hundred fifteen thousand, four hundred seventy-one".
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