Base | Representation |
---|---|
bin | 110001010111001101… |
… | …101110111100011101 |
3 | 12001210212011111211011 |
4 | 301113031232330131 |
5 | 1332022210404001 |
6 | 40203230255221 |
7 | 3554313404023 |
oct | 612715567435 |
9 | 161725144734 |
10 | 53002825501 |
11 | 2052979331a |
12 | a332657511 |
13 | 4cc8c03352 |
14 | 27cb470713 |
15 | 15a32e5d51 |
hex | c5736ef1d |
53002825501 has 2 divisors, whose sum is σ = 53002825502. Its totient is φ = 53002825500.
The previous prime is 53002825493. The next prime is 53002825511. The reversal of 53002825501 is 10552820035.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 42952562500 + 10050263001 = 207250^2 + 100251^2 .
It is a cyclic number.
It is not a de Polignac number, because 53002825501 - 23 = 53002825493 is a prime.
It is a super-2 number, since 2×530028255012 (a number of 22 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53002825511) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26501412750 + 26501412751.
It is an arithmetic number, because the mean of its divisors is an integer number (26501412751).
Almost surely, 253002825501 is an apocalyptic number.
It is an amenable number.
53002825501 is a deficient number, since it is larger than the sum of its proper divisors (1).
53002825501 is an equidigital number, since it uses as much as digits as its factorization.
53002825501 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12000, while the sum is 31.
The spelling of 53002825501 in words is "fifty-three billion, two million, eight hundred twenty-five thousand, five hundred one".
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