Base | Representation |
---|---|
bin | 110001010111001111… |
… | …101111110000010111 |
3 | 12001210220011022120021 |
4 | 301113033233300113 |
5 | 1332022324244421 |
6 | 40203245450011 |
7 | 3554321032162 |
oct | 612717576027 |
9 | 161726138507 |
10 | 53003353111 |
11 | 2052a013765 |
12 | a332870907 |
13 | 4cc9059547 |
14 | 27cb56aad9 |
15 | 15a339c341 |
hex | c573efc17 |
53003353111 has 2 divisors, whose sum is σ = 53003353112. Its totient is φ = 53003353110.
The previous prime is 53003353087. The next prime is 53003353217. The reversal of 53003353111 is 11135330035.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 53003353111 - 25 = 53003353079 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53003353511) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26501676555 + 26501676556.
It is an arithmetic number, because the mean of its divisors is an integer number (26501676556).
Almost surely, 253003353111 is an apocalyptic number.
53003353111 is a deficient number, since it is larger than the sum of its proper divisors (1).
53003353111 is an equidigital number, since it uses as much as digits as its factorization.
53003353111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2025, while the sum is 25.
Adding to 53003353111 its reverse (11135330035), we get a palindrome (64138683146).
The spelling of 53003353111 in words is "fifty-three billion, three million, three hundred fifty-three thousand, one hundred eleven".
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