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530034004121 is a prime number
BaseRepresentation
bin1111011011010000111…
…11010001000010011001
31212200002222111012111112
413231220133101002121
532141002201112441
61043254432110105
753202510461516
oct7555037210231
91780088435445
10530034004121
11194871417306
1286883395335
133ac9c58a54b
141b921da030d
15dbc27274eb
hex7b687d1099

530034004121 has 2 divisors, whose sum is σ = 530034004122. Its totient is φ = 530034004120.

The previous prime is 530034004091. The next prime is 530034004153. The reversal of 530034004121 is 121400430035.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 473013817600 + 57020186521 = 687760^2 + 238789^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-530034004121 is a prime.

It is a super-3 number, since 3×5300340041213 (a number of 36 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (530034007121) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265017002060 + 265017002061.

It is an arithmetic number, because the mean of its divisors is an integer number (265017002061).

Almost surely, 2530034004121 is an apocalyptic number.

It is an amenable number.

530034004121 is a deficient number, since it is larger than the sum of its proper divisors (1).

530034004121 is an equidigital number, since it uses as much as digits as its factorization.

530034004121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1440, while the sum is 23.

Adding to 530034004121 its reverse (121400430035), we get a palindrome (651434434156).

The spelling of 530034004121 in words is "five hundred thirty billion, thirty-four million, four thousand, one hundred twenty-one".