Base | Representation |
---|---|
bin | 1111011011010000111… |
… | …11010001000010011001 |
3 | 1212200002222111012111112 |
4 | 13231220133101002121 |
5 | 32141002201112441 |
6 | 1043254432110105 |
7 | 53202510461516 |
oct | 7555037210231 |
9 | 1780088435445 |
10 | 530034004121 |
11 | 194871417306 |
12 | 86883395335 |
13 | 3ac9c58a54b |
14 | 1b921da030d |
15 | dbc27274eb |
hex | 7b687d1099 |
530034004121 has 2 divisors, whose sum is σ = 530034004122. Its totient is φ = 530034004120.
The previous prime is 530034004091. The next prime is 530034004153. The reversal of 530034004121 is 121400430035.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 473013817600 + 57020186521 = 687760^2 + 238789^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-530034004121 is a prime.
It is a super-3 number, since 3×5300340041213 (a number of 36 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (530034007121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265017002060 + 265017002061.
It is an arithmetic number, because the mean of its divisors is an integer number (265017002061).
Almost surely, 2530034004121 is an apocalyptic number.
It is an amenable number.
530034004121 is a deficient number, since it is larger than the sum of its proper divisors (1).
530034004121 is an equidigital number, since it uses as much as digits as its factorization.
530034004121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1440, while the sum is 23.
Adding to 530034004121 its reverse (121400430035), we get a palindrome (651434434156).
The spelling of 530034004121 in words is "five hundred thirty billion, thirty-four million, four thousand, one hundred twenty-one".
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