Base | Representation |
---|---|
bin | 110001010111010011… |
… | …111011110110011111 |
3 | 12001210222020002220101 |
4 | 301113103323312133 |
5 | 1332023114414411 |
6 | 40203325201531 |
7 | 3554333254534 |
oct | 612723736637 |
9 | 161728202811 |
10 | 53004451231 |
11 | 2052a6a37a6 |
12 | a3331002a7 |
13 | 4cc9352314 |
14 | 27cb774d8b |
15 | 15a35178c1 |
hex | c574fbd9f |
53004451231 has 4 divisors (see below), whose sum is σ = 53027389264. Its totient is φ = 52981513200.
The previous prime is 53004451219. The next prime is 53004451237. The reversal of 53004451231 is 13215440035.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 53004451231 - 27 = 53004451103 is a prime.
It is a super-2 number, since 2×530044512312 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 53004451231.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53004451237) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11465550 + ... + 11470171.
It is an arithmetic number, because the mean of its divisors is an integer number (13256847316).
Almost surely, 253004451231 is an apocalyptic number.
53004451231 is a deficient number, since it is larger than the sum of its proper divisors (22938033).
53004451231 is a wasteful number, since it uses less digits than its factorization.
53004451231 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 22938032.
The product of its (nonzero) digits is 7200, while the sum is 28.
Adding to 53004451231 its reverse (13215440035), we get a palindrome (66219891266).
The spelling of 53004451231 in words is "fifty-three billion, four million, four hundred fifty-one thousand, two hundred thirty-one".
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