Base | Representation |
---|---|
bin | 100110100100001111010… |
… | …1110101110110110111101 |
3 | 200202201112022200111101221 |
4 | 1031020132232232312331 |
5 | 1143320413313212201 |
6 | 15135003554033341 |
7 | 1054643313622030 |
oct | 115103656566675 |
9 | 20681468614357 |
10 | 5300505210301 |
11 | 1763a28009834 |
12 | 717334578851 |
13 | 2c5ab2780682 |
14 | 14478da39017 |
15 | 92d294274a1 |
hex | 4d21ebaedbd |
5300505210301 has 4 divisors (see below), whose sum is σ = 6057720240352. Its totient is φ = 4543290180252.
The previous prime is 5300505210289. The next prime is 5300505210317. The reversal of 5300505210301 is 1030125050035.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 5300505210301 - 25 = 5300505210269 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5300505210901) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 378607515015 + ... + 378607515028.
It is an arithmetic number, because the mean of its divisors is an integer number (1514430060088).
Almost surely, 25300505210301 is an apocalyptic number.
It is an amenable number.
5300505210301 is a deficient number, since it is larger than the sum of its proper divisors (757215030051).
5300505210301 is an equidigital number, since it uses as much as digits as its factorization.
5300505210301 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 757215030050.
The product of its (nonzero) digits is 2250, while the sum is 25.
The spelling of 5300505210301 in words is "five trillion, three hundred billion, five hundred five million, two hundred ten thousand, three hundred one".
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