Base | Representation |
---|---|
bin | 111100010000101001010111… |
… | …0101001101111101111011111 |
3 | 2120111202121120011222120221112 |
4 | 1320201102232221233233133 |
5 | 1023433343413113103431 |
6 | 5115155104103252235 |
7 | 216435045140123105 |
oct | 17041225651575737 |
9 | 2514677504876845 |
10 | 530053434112991 |
11 | 143989443101888 |
12 | 4b547aa674a07b |
13 | 1999ba94180879 |
14 | 94c6a1a263c75 |
15 | 4142d8d7b1c2b |
hex | 1e214aea6fbdf |
530053434112991 has 2 divisors, whose sum is σ = 530053434112992. Its totient is φ = 530053434112990.
The previous prime is 530053434112927. The next prime is 530053434113053. The reversal of 530053434112991 is 199211434350035.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 530053434112991 - 26 = 530053434112927 is a prime.
It is a super-2 number, since 2×5300534341129912 (a number of 30 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (530053434112901) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265026717056495 + 265026717056496.
It is an arithmetic number, because the mean of its divisors is an integer number (265026717056496).
Almost surely, 2530053434112991 is an apocalyptic number.
530053434112991 is a deficient number, since it is larger than the sum of its proper divisors (1).
530053434112991 is an equidigital number, since it uses as much as digits as its factorization.
530053434112991 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1749600, while the sum is 50.
The spelling of 530053434112991 in words is "five hundred thirty trillion, fifty-three billion, four hundred thirty-four million, one hundred twelve thousand, nine hundred ninety-one".
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