Base | Representation |
---|---|
bin | 11000000110110011000001… |
… | …10101011111000110101001 |
3 | 20221200201100210001121110112 |
4 | 30003121200311133012221 |
5 | 23422004201404013001 |
6 | 304424301522424105 |
7 | 14110565652651230 |
oct | 1403314065370651 |
9 | 227621323047415 |
10 | 53010111001001 |
11 | 15988509764540 |
12 | 5b4186ab02035 |
13 | 2376aa7c361bb |
14 | d139bb2b9b17 |
15 | 61ddabd8acbb |
hex | 303660d5f1a9 |
53010111001001 has 16 divisors (see below), whose sum is σ = 66090789371520. Its totient is φ = 41306416644480.
The previous prime is 53010111000971. The next prime is 53010111001007. The reversal of 53010111001001 is 10010011101035.
It is a cyclic number.
It is not a de Polignac number, because 53010111001001 - 242 = 48612064489897 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (53010111001007) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 20500595 + ... + 22941111.
It is an arithmetic number, because the mean of its divisors is an integer number (4130674335720).
Almost surely, 253010111001001 is an apocalyptic number.
It is an amenable number.
53010111001001 is a deficient number, since it is larger than the sum of its proper divisors (13080678370519).
53010111001001 is a wasteful number, since it uses less digits than its factorization.
53010111001001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2722624.
The product of its (nonzero) digits is 15, while the sum is 14.
Adding to 53010111001001 its reverse (10010011101035), we get a palindrome (63020122102036).
The spelling of 53010111001001 in words is "fifty-three trillion, ten billion, one hundred eleven million, one thousand, one".
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