Base | Representation |
---|---|
bin | 111100010001000000100101… |
… | …0111010111101011100101010 |
3 | 2120111221101021110102002211010 |
4 | 1320202001022322331130222 |
5 | 1023440203024412332110 |
6 | 5115234032213244350 |
7 | 216441461650405164 |
oct | 17042011272753452 |
9 | 2514841243362733 |
10 | 530103300511530 |
11 | 1439a86024130a9 |
12 | 4b5556a29336b6 |
13 | 199a36b0343775 |
14 | 94c91cad37934 |
15 | 414430b566020 |
hex | 1e2204aebd72a |
530103300511530 has 64 divisors (see below), whose sum is σ = 1320769135359360. Its totient is φ = 136004082982656.
The previous prime is 530103300511513. The next prime is 530103300511541. The reversal of 530103300511530 is 35115003301035.
It is a super-4 number, since 4×5301033005115304 (a number of 60 digits) contains 4444 as substring.
It is a Harshad number since it is a multiple of its sum of digits (30).
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1076280537 + ... + 1076772956.
It is an arithmetic number, because the mean of its divisors is an integer number (20637017739990).
Almost surely, 2530103300511530 is an apocalyptic number.
530103300511530 is an abundant number, since it is smaller than the sum of its proper divisors (790665834847830).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
530103300511530 is a wasteful number, since it uses less digits than its factorization.
530103300511530 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2153053815.
The product of its (nonzero) digits is 10125, while the sum is 30.
Adding to 530103300511530 its reverse (35115003301035), we get a palindrome (565218303812565).
The spelling of 530103300511530 in words is "five hundred thirty trillion, one hundred three billion, three hundred million, five hundred eleven thousand, five hundred thirty".
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