Base | Representation |
---|---|
bin | 11000000110110011110010… |
… | …11011000101111000010111 |
3 | 20221200202102112021100122101 |
4 | 30003121321123011320113 |
5 | 23422011023004343333 |
6 | 304424410500142531 |
7 | 14110612122152215 |
oct | 1403317133057027 |
9 | 227622375240571 |
10 | 53010523512343 |
11 | 159887005a5401 |
12 | 5b41965097a47 |
13 | 2376b42538457 |
14 | d13a19db9cb5 |
15 | 61ddd31c167d |
hex | 3036796c5e17 |
53010523512343 has 2 divisors, whose sum is σ = 53010523512344. Its totient is φ = 53010523512342.
The previous prime is 53010523512319. The next prime is 53010523512451. The reversal of 53010523512343 is 34321532501035.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 53010523512343 - 213 = 53010523504151 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53010523515343) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26505261756171 + 26505261756172.
It is an arithmetic number, because the mean of its divisors is an integer number (26505261756172).
Almost surely, 253010523512343 is an apocalyptic number.
53010523512343 is a deficient number, since it is larger than the sum of its proper divisors (1).
53010523512343 is an equidigital number, since it uses as much as digits as its factorization.
53010523512343 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 162000, while the sum is 37.
The spelling of 53010523512343 in words is "fifty-three trillion, ten billion, five hundred twenty-three million, five hundred twelve thousand, three hundred forty-three".
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