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530105403 = 3237682687
BaseRepresentation
bin11111100110001…
…100010000111011
31100221111010220110
4133212030100323
52041201333103
6124333555403
716064551542
oct3746142073
91327433813
10530105403
1125225a043
12129645b63
1385a96049
1450591159
1531813403
hex1f98c43b

530105403 has 8 divisors (see below), whose sum is σ = 737538048. Its totient is φ = 338038184.

The previous prime is 530105399. The next prime is 530105423. The reversal of 530105403 is 304501035.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 530105403 - 22 = 530105399 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 530105403.

It is not an unprimeable number, because it can be changed into a prime (530105423) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3841275 + ... + 3841412.

It is an arithmetic number, because the mean of its divisors is an integer number (92192256).

Almost surely, 2530105403 is an apocalyptic number.

530105403 is a deficient number, since it is larger than the sum of its proper divisors (207432645).

530105403 is a wasteful number, since it uses less digits than its factorization.

530105403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7682713.

The product of its (nonzero) digits is 900, while the sum is 21.

The square root of 530105403 is about 23024.0179595135. The cubic root of 530105403 is about 809.3208771927.

Adding to 530105403 its reverse (304501035), we get a palindrome (834606438).

The spelling of 530105403 in words is "five hundred thirty million, one hundred five thousand, four hundred three".

Divisors: 1 3 23 69 7682687 23048061 176701801 530105403