Base | Representation |
---|---|
bin | 100110100100011111101… |
… | …1101010110010010000101 |
3 | 200202202221120220012200020 |
4 | 1031020333131112102011 |
5 | 1143323024400120232 |
6 | 15135134251005353 |
7 | 1054663032046335 |
oct | 115107735262205 |
9 | 20682846805606 |
10 | 5301054301317 |
11 | 1764189a55a65 |
12 | 717468439859 |
13 | 2c5b6c4631b8 |
14 | 14480292d0c5 |
15 | 92d5c73ae2c |
hex | 4d23f756485 |
5301054301317 has 8 divisors (see below), whose sum is σ = 7068340531680. Its totient is φ = 3533902135920.
The previous prime is 5301054301261. The next prime is 5301054301343. The reversal of 5301054301317 is 7131034501035.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 5301054301317 - 211 = 5301054299269 is a prime.
It is a super-2 number, since 2×53010543013172 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5301054301357) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 33423942 + ... + 33582167.
It is an arithmetic number, because the mean of its divisors is an integer number (883542566460).
Almost surely, 25301054301317 is an apocalyptic number.
It is an amenable number.
5301054301317 is a deficient number, since it is larger than the sum of its proper divisors (1767286230363).
5301054301317 is a wasteful number, since it uses less digits than its factorization.
5301054301317 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 67032483.
The product of its (nonzero) digits is 18900, while the sum is 33.
The spelling of 5301054301317 in words is "five trillion, three hundred one billion, fifty-four million, three hundred one thousand, three hundred seventeen".
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