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53011003 = 67791209
BaseRepresentation
bin1100101000111…
…0001000111011
310200202020102111
43022032020323
5102032323003
65132113151
71212405013
oct312161073
9120666374
1053011003
1127a17a51
12159057b7
13aca0a76
14707cc43
1549c1e6d
hex328e23b

53011003 has 4 divisors (see below), whose sum is σ = 53802280. Its totient is φ = 52219728.

The previous prime is 53011001. The next prime is 53011031. The reversal of 53011003 is 30011035.

53011003 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 53011003 - 21 = 53011001 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (53011001) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 395538 + ... + 395671.

It is an arithmetic number, because the mean of its divisors is an integer number (13450570).

Almost surely, 253011003 is an apocalyptic number.

53011003 is a deficient number, since it is larger than the sum of its proper divisors (791277).

53011003 is an equidigital number, since it uses as much as digits as its factorization.

53011003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 791276.

The product of its (nonzero) digits is 45, while the sum is 13.

The square root of 53011003 is about 7280.8655392062. The cubic root of 53011003 is about 375.6545675934.

Adding to 53011003 its reverse (30011035), we get a palindrome (83022038).

The spelling of 53011003 in words is "fifty-three million, eleven thousand, three".

Divisors: 1 67 791209 53011003