Base | Representation |
---|---|
bin | 100110100100100010001… |
… | …0001101100001100010111 |
3 | 200202210011012222210201120 |
4 | 1031021010101230030113 |
5 | 1143323211043201130 |
6 | 15135150255255023 |
7 | 1054665033100524 |
oct | 115110421541427 |
9 | 20683135883646 |
10 | 5301135131415 |
11 | 17642206438a2 |
12 | 71748b51a473 |
13 | 2c5b83124366 |
14 | 14480d57014b |
15 | 92d648a5910 |
hex | 4d24446c317 |
5301135131415 has 16 divisors (see below), whose sum is σ = 8688689777376. Its totient is φ = 2758314214400.
The previous prime is 5301135131407. The next prime is 5301135131417. The reversal of 5301135131415 is 5141315311035.
It is not a de Polignac number, because 5301135131415 - 23 = 5301135131407 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5301135131417) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4309865346 + ... + 4309866575.
It is an arithmetic number, because the mean of its divisors is an integer number (543043111086).
Almost surely, 25301135131415 is an apocalyptic number.
5301135131415 is a deficient number, since it is larger than the sum of its proper divisors (3387554645961).
5301135131415 is a wasteful number, since it uses less digits than its factorization.
5301135131415 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8619731970.
The product of its (nonzero) digits is 13500, while the sum is 33.
The spelling of 5301135131415 in words is "five trillion, three hundred one billion, one hundred thirty-five million, one hundred thirty-one thousand, four hundred fifteen".
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