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53012442631 is a prime number
BaseRepresentation
bin110001010111110010…
…011010111000000111
312001211112021010001011
4301113302122320013
51332032141131011
640204212343051
73554461220221
oct612762327007
9161745233034
1053012442631
1120534161865
12a335914a87
134ccabbc865
1427cc855411
1515a4095621
hexc57c9ae07

53012442631 has 2 divisors, whose sum is σ = 53012442632. Its totient is φ = 53012442630.

The previous prime is 53012442611. The next prime is 53012442641. The reversal of 53012442631 is 13624421035.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-53012442631 is a prime.

It is a super-2 number, since 2×530124426312 (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 53012442593 and 53012442602.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (53012442611) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26506221315 + 26506221316.

It is an arithmetic number, because the mean of its divisors is an integer number (26506221316).

Almost surely, 253012442631 is an apocalyptic number.

53012442631 is a deficient number, since it is larger than the sum of its proper divisors (1).

53012442631 is an equidigital number, since it uses as much as digits as its factorization.

53012442631 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 17280, while the sum is 31.

Adding to 53012442631 its reverse (13624421035), we get a palindrome (66636863666).

The spelling of 53012442631 in words is "fifty-three billion, twelve million, four hundred forty-two thousand, six hundred thirty-one".