Base | Representation |
---|---|
bin | 110001010111110010… |
… | …011010111000000111 |
3 | 12001211112021010001011 |
4 | 301113302122320013 |
5 | 1332032141131011 |
6 | 40204212343051 |
7 | 3554461220221 |
oct | 612762327007 |
9 | 161745233034 |
10 | 53012442631 |
11 | 20534161865 |
12 | a335914a87 |
13 | 4ccabbc865 |
14 | 27cc855411 |
15 | 15a4095621 |
hex | c57c9ae07 |
53012442631 has 2 divisors, whose sum is σ = 53012442632. Its totient is φ = 53012442630.
The previous prime is 53012442611. The next prime is 53012442641. The reversal of 53012442631 is 13624421035.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-53012442631 is a prime.
It is a super-2 number, since 2×530124426312 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 53012442593 and 53012442602.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53012442611) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26506221315 + 26506221316.
It is an arithmetic number, because the mean of its divisors is an integer number (26506221316).
Almost surely, 253012442631 is an apocalyptic number.
53012442631 is a deficient number, since it is larger than the sum of its proper divisors (1).
53012442631 is an equidigital number, since it uses as much as digits as its factorization.
53012442631 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 17280, while the sum is 31.
Adding to 53012442631 its reverse (13624421035), we get a palindrome (66636863666).
The spelling of 53012442631 in words is "fifty-three billion, twelve million, four hundred forty-two thousand, six hundred thirty-one".
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