53012505437 has 2 divisors, whose sum is σ = 53012505438. Its totient is φ = 53012505436.

The previous prime is 53012505433. The next prime is 53012505463. The reversal of 53012505437 is 73450521035.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 36376407076 + 16636098361 = 190726^2 + 128981^2 .

It is a cyclic number.

It is not a de Polignac number, because 53012505437 - 2² = 53012505433 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 53012505397 and 53012505406.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (53012505433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26506252718 + 26506252719.

It is an arithmetic number, because the mean of its divisors is an integer number (26506252719).

Almost surely, 2^53012505437 is an apocalyptic number.

It is an amenable number.

53012505437 is a deficient number, since it is larger than the sum of its proper divisors (1).

53012505437 is an equidigital number, since it uses as much as digits as its factorization.

53012505437 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 63000, while the sum is 35.

The spelling of 53012505437 in words is "fifty-three billion, twelve million, five hundred five thousand, four hundred thirty-seven".