Base | Representation |
---|---|
bin | 11000000110110111101100… |
… | …11010101000010111100101 |
3 | 20221200221211200012120112120 |
4 | 30003123312122220113211 |
5 | 23422024321324342321 |
6 | 304425354530540153 |
7 | 14111015104502445 |
oct | 1403336632502745 |
9 | 227627750176476 |
10 | 53012620543461 |
11 | 15989587295977 |
12 | 5b4224b437659 |
13 | 23770b7b26b77 |
14 | d13b786d2125 |
15 | 61dea734dec6 |
hex | 3036f66a85e5 |
53012620543461 has 32 divisors (see below), whose sum is σ = 74883219406848. Its totient is φ = 33244215755520.
The previous prime is 53012620543459. The next prime is 53012620543583. The reversal of 53012620543461 is 16434502621035.
It is not a de Polignac number, because 53012620543461 - 21 = 53012620543459 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53012620543261) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 731868916 + ... + 731941346.
It is an arithmetic number, because the mean of its divisors is an integer number (2340100606464).
Almost surely, 253012620543461 is an apocalyptic number.
53012620543461 is a gapful number since it is divisible by the number (51) formed by its first and last digit.
It is an amenable number.
53012620543461 is a deficient number, since it is larger than the sum of its proper divisors (21870598863387).
53012620543461 is a wasteful number, since it uses less digits than its factorization.
53012620543461 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 80281.
The product of its (nonzero) digits is 518400, while the sum is 42.
The spelling of 53012620543461 in words is "fifty-three trillion, twelve billion, six hundred twenty million, five hundred forty-three thousand, four hundred sixty-one".
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