530130031035 has 16 divisors (see below), whose sum is σ = 925317872640. Its totient is φ = 257032742240.

The previous prime is 530130031031. The next prime is 530130031069.

530130031035 is nontrivially palindromic in base 10.

It is not a de Polignac number, because 530130031035 - 2² = 530130031031 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 530130030996 and 530130031014.

It is not an unprimeable number, because it can be changed into a prime (530130031031) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1606454475 + ... + 1606454804.

It is an arithmetic number, because the mean of its divisors is an integer number (57832367040).

Almost surely, 2^530130031035 is an apocalyptic number.

530130031035 is a gapful number since it is divisible by the number (55) formed by its first and last digit.

530130031035 is a deficient number, since it is larger than the sum of its proper divisors (395187841605).

530130031035 is a wasteful number, since it uses less digits than its factorization.

530130031035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3212909298.

The product of its (nonzero) digits is 2025, while the sum is 24.

It can be divided in two parts, 5301300 and 31035, that added together give a palindrome (5332335).

The spelling of 530130031035 in words is "five hundred thirty billion, one hundred thirty million, thirty-one thousand, thirty-five".