Base | Representation |
---|---|
bin | 110001010111110100… |
… | …101101000100001101 |
3 | 12001211120101112102120 |
4 | 301113310231010031 |
5 | 1332032314311141 |
6 | 40204233243153 |
7 | 3554466263034 |
oct | 612764550415 |
9 | 161746345376 |
10 | 53013041421 |
11 | 2053453072a |
12 | a335b634b9 |
13 | 4ccb06c282 |
14 | 27cc96d71b |
15 | 15a4162c66 |
hex | c57d2d10d |
53013041421 has 16 divisors (see below), whose sum is σ = 71309721600. Its totient is φ = 35029734768.
The previous prime is 53013041413. The next prime is 53013041423. The reversal of 53013041421 is 12414031035.
It is a happy number.
53013041421 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 53013041421 - 23 = 53013041413 is a prime.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 53013041391 and 53013041400.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53013041423) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 328900 + ... + 462818.
It is an arithmetic number, because the mean of its divisors is an integer number (4456857600).
Almost surely, 253013041421 is an apocalyptic number.
It is an amenable number.
53013041421 is a deficient number, since it is larger than the sum of its proper divisors (18296680179).
53013041421 is a wasteful number, since it uses less digits than its factorization.
53013041421 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 135088.
The product of its (nonzero) digits is 1440, while the sum is 24.
Adding to 53013041421 its reverse (12414031035), we get a palindrome (65427072456).
The spelling of 53013041421 in words is "fifty-three billion, thirteen million, forty-one thousand, four hundred twenty-one".
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