Base | Representation |
---|---|
bin | 110001010111110100… |
… | …111100011111101111 |
3 | 12001211120111202010101 |
4 | 301113310330133233 |
5 | 1332032323321443 |
6 | 40204234451531 |
7 | 3554466645223 |
oct | 612764743757 |
9 | 161746452111 |
10 | 53013104623 |
11 | 20534574166 |
12 | a335b93ba7 |
13 | 4ccb091c7b |
14 | 27cc988783 |
15 | 15a417684d |
hex | c57d3c7ef |
53013104623 has 16 divisors (see below), whose sum is σ = 57114270720. Its totient is φ = 49022064000.
The previous prime is 53013104611. The next prime is 53013104633. The reversal of 53013104623 is 32640131035.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-53013104623 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 53013104591 and 53013104600.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53013104633) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1943308 + ... + 1970398.
It is an arithmetic number, because the mean of its divisors is an integer number (3569641920).
Almost surely, 253013104623 is an apocalyptic number.
53013104623 is a deficient number, since it is larger than the sum of its proper divisors (4101166097).
53013104623 is a wasteful number, since it uses less digits than its factorization.
53013104623 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 29118.
The product of its (nonzero) digits is 6480, while the sum is 28.
Adding to 53013104623 its reverse (32640131035), we get a palindrome (85653235658).
The spelling of 53013104623 in words is "fifty-three billion, thirteen million, one hundred four thousand, six hundred twenty-three".
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