Base | Representation |
---|---|
bin | 110001010111110101… |
… | …101111001011110111 |
3 | 12001211120220021221011 |
4 | 301113311233023313 |
5 | 1332032401442442 |
6 | 40204243133051 |
7 | 3554501501440 |
oct | 612765571367 |
9 | 161746807834 |
10 | 53013312247 |
11 | 205346a6155 |
12 | a336074187 |
13 | 4ccb13561c |
14 | 27cca002c7 |
15 | 15a41b8117 |
hex | c57d6f2f7 |
53013312247 has 8 divisors (see below), whose sum is σ = 60589527552. Its totient is φ = 45437818200.
The previous prime is 53013312241. The next prime is 53013312259. The reversal of 53013312247 is 74221331035.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 53013312247 - 23 = 53013312239 is a prime.
It is a super-2 number, since 2×530133122472 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53013312241) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 12379 + ... + 325852.
It is an arithmetic number, because the mean of its divisors is an integer number (7573690944).
Almost surely, 253013312247 is an apocalyptic number.
53013312247 is a deficient number, since it is larger than the sum of its proper divisors (7576215305).
53013312247 is a wasteful number, since it uses less digits than its factorization.
53013312247 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 360629.
The product of its (nonzero) digits is 15120, while the sum is 31.
The spelling of 53013312247 in words is "fifty-three billion, thirteen million, three hundred twelve thousand, two hundred forty-seven".
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