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53014041035 = 510602808207
BaseRepresentation
bin110001010111111000…
…100001000111001011
312001211122021022122022
4301113320201013023
51332033043303120
640204310515055
73554510625254
oct612770410713
9161748238568
1053014041035
112053505375a
12a336365a8b
134ccb32c267
1427ccb4db2b
1515a42ae025
hexc57e211cb

53014041035 has 4 divisors (see below), whose sum is σ = 63616849248. Its totient is φ = 42411232824.

The previous prime is 53014041019. The next prime is 53014041043.

53014041035 is nontrivially palindromic in base 10.

53014041035 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 53014041035 - 24 = 53014041019 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 53014040995 and 53014041013.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5301404099 + ... + 5301404108.

It is an arithmetic number, because the mean of its divisors is an integer number (15904212312).

Almost surely, 253014041035 is an apocalyptic number.

53014041035 is a deficient number, since it is larger than the sum of its proper divisors (10602808213).

53014041035 is a wasteful number, since it uses less digits than its factorization.

53014041035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10602808212.

The product of its (nonzero) digits is 3600, while the sum is 26.

It can be divided in two parts, 530140 and 41035, that added together give a palindrome (571175).

The spelling of 53014041035 in words is "fifty-three billion, fourteen million, forty-one thousand, thirty-five".

Divisors: 1 5 10602808207 53014041035