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53014111 is a prime number
BaseRepresentation
bin1100101000111…
…0111001011111
310200202101200121
43022032321133
5102032422421
65132135411
71212420043
oct312167137
9120671617
1053014111
1127a1a317
1215907567
13aca22c7
147080023
1549c2d41
hex328ee5f

53014111 has 2 divisors, whose sum is σ = 53014112. Its totient is φ = 53014110.

The previous prime is 53014099. The next prime is 53014121. The reversal of 53014111 is 11141035.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-53014111 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (53014121) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26507055 + 26507056.

It is an arithmetic number, because the mean of its divisors is an integer number (26507056).

Almost surely, 253014111 is an apocalyptic number.

53014111 is a deficient number, since it is larger than the sum of its proper divisors (1).

53014111 is an equidigital number, since it uses as much as digits as its factorization.

53014111 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 60, while the sum is 16.

The square root of 53014111 is about 7281.0789722403. The cubic root of 53014111 is about 375.6619089094.

Adding to 53014111 its reverse (11141035), we get a palindrome (64155146).

It can be divided in two parts, 530 and 14111, that added together give a palindrome (14641).

The spelling of 53014111 in words is "fifty-three million, fourteen thousand, one hundred eleven".