Base | Representation |
---|---|
bin | 111100010001010011001011… |
… | …0011100101001110110101011 |
3 | 2120112002012022200101011120002 |
4 | 1320202212112130221312223 |
5 | 1023441331304404403120 |
6 | 5115304233440453215 |
7 | 216444404155352522 |
oct | 17042462634516653 |
9 | 2515065280334502 |
10 | 530143222341035 |
11 | 143a1352922a526 |
12 | 4b56138461a20b |
13 | 199a73a31565a4 |
14 | 94cb0d6d974b9 |
15 | 414539625b375 |
hex | 1e22996729dab |
530143222341035 has 8 divisors (see below), whose sum is σ = 636196733939520. Its totient is φ = 424097999785984.
The previous prime is 530143222340999. The next prime is 530143222341091.
530143222341035 is nontrivially palindromic in base 10.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-530143222341035 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 530143222341035.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2072120150 + ... + 2072375979.
It is an arithmetic number, because the mean of its divisors is an integer number (79524591742440).
Almost surely, 2530143222341035 is an apocalyptic number.
530143222341035 is a deficient number, since it is larger than the sum of its proper divisors (106053511598485).
530143222341035 is a wasteful number, since it uses less digits than its factorization.
530143222341035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4144521717.
The product of its (nonzero) digits is 259200, while the sum is 38.
The spelling of 530143222341035 in words is "five hundred thirty trillion, one hundred forty-three billion, two hundred twenty-two million, three hundred forty-one thousand, thirty-five".
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