Base | Representation |
---|---|
bin | 110001010111111010… |
… | …011001001111111111 |
3 | 12001211200012022122122 |
4 | 301113322121033333 |
5 | 1332033210024434 |
6 | 40204325233155 |
7 | 3554515045022 |
oct | 612772311777 |
9 | 161750168578 |
10 | 53014533119 |
11 | 2053535a439 |
12 | a3365627bb |
13 | 4ccb472232 |
14 | 27ccc3b1b9 |
15 | 15a4359c2e |
hex | c57e993ff |
53014533119 has 2 divisors, whose sum is σ = 53014533120. Its totient is φ = 53014533118.
The previous prime is 53014533109. The next prime is 53014533149. The reversal of 53014533119 is 91133541035.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 53014533119 - 212 = 53014529023 is a prime.
It is a super-2 number, since 2×530145331192 (a number of 22 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53014533109) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26507266559 + 26507266560.
It is an arithmetic number, because the mean of its divisors is an integer number (26507266560).
Almost surely, 253014533119 is an apocalyptic number.
53014533119 is a deficient number, since it is larger than the sum of its proper divisors (1).
53014533119 is an equidigital number, since it uses as much as digits as its factorization.
53014533119 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24300, while the sum is 35.
The spelling of 53014533119 in words is "fifty-three billion, fourteen million, five hundred thirty-three thousand, one hundred nineteen".
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