Base | Representation |
---|---|
bin | 111100010001010110100100… |
… | …1110011100101111001101111 |
3 | 2120112002220011201022222222111 |
4 | 1320202231021303211321233 |
5 | 1023441441234232134434 |
6 | 5115311442321024451 |
7 | 216445053156245011 |
oct | 17042551163457157 |
9 | 2515086151288874 |
10 | 530150526443119 |
11 | 143a166371aa52a |
12 | 4b562882785127 |
13 | 199a7c9846549a |
14 | 94cb5cb0741b1 |
15 | 41456725e4964 |
hex | 1e22b49ce5e6f |
530150526443119 has 2 divisors, whose sum is σ = 530150526443120. Its totient is φ = 530150526443118.
The previous prime is 530150526442993. The next prime is 530150526443137. The reversal of 530150526443119 is 911344625051035.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 530150526443119 - 219 = 530150525918831 is a prime.
It is a super-2 number, since 2×5301505264431192 (a number of 30 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (530150526447119) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265075263221559 + 265075263221560.
It is an arithmetic number, because the mean of its divisors is an integer number (265075263221560).
Almost surely, 2530150526443119 is an apocalyptic number.
530150526443119 is a deficient number, since it is larger than the sum of its proper divisors (1).
530150526443119 is an equidigital number, since it uses as much as digits as its factorization.
530150526443119 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1944000, while the sum is 49.
The spelling of 530150526443119 in words is "five hundred thirty trillion, one hundred fifty billion, five hundred twenty-six million, four hundred forty-three thousand, one hundred nineteen".
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