Base | Representation |
---|---|
bin | 100110100100101101010… |
… | …1011101011100001000111 |
3 | 200202211010102100002200011 |
4 | 1031021122223223201013 |
5 | 1143324443311340033 |
6 | 15135251444331051 |
7 | 1055010246225220 |
oct | 115113253534107 |
9 | 20684112302604 |
10 | 5301511043143 |
11 | 17643a3856947 |
12 | 7175753a3a87 |
13 | 2c5c12c80733 |
14 | 144847464247 |
15 | 92d878abccd |
hex | 4d25aaeb847 |
5301511043143 has 8 divisors (see below), whose sum is σ = 6058890853920. Its totient is φ = 4544136504960.
The previous prime is 5301511043123. The next prime is 5301511043149. The reversal of 5301511043143 is 3413401151035.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5301511043143 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5301511043149) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1142763 + ... + 3450931.
It is an arithmetic number, because the mean of its divisors is an integer number (757361356740).
Almost surely, 25301511043143 is an apocalyptic number.
5301511043143 is a deficient number, since it is larger than the sum of its proper divisors (757379810777).
5301511043143 is a wasteful number, since it uses less digits than its factorization.
5301511043143 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2636297.
The product of its (nonzero) digits is 10800, while the sum is 31.
Adding to 5301511043143 its reverse (3413401151035), we get a palindrome (8714912194178).
The spelling of 5301511043143 in words is "five trillion, three hundred one billion, five hundred eleven million, forty-three thousand, one hundred forty-three".
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