Base | Representation |
---|---|
bin | 11000000110111101100101… |
… | …00111111010000000000001 |
3 | 20221201020222201210002220111 |
4 | 30003132302213322000001 |
5 | 23422102303200441121 |
6 | 304431040125111321 |
7 | 14111156255564644 |
oct | 1403366247720001 |
9 | 227636881702814 |
10 | 53015778140161 |
11 | 1598a957707021 |
12 | 5b429909b8541 |
13 | 237749c069c95 |
14 | d13d97bdda5b |
15 | 61e0de6732e1 |
hex | 3037b29fa001 |
53015778140161 has 12 divisors (see below), whose sum is σ = 55754510961072. Its totient is φ = 50383316441808.
The previous prime is 53015778140153. The next prime is 53015778140201. The reversal of 53015778140161 is 16104187751035.
It is not a de Polignac number, because 53015778140161 - 23 = 53015778140153 is a prime.
It is a super-2 number, since 2×530157781401612 (a number of 28 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (53015778140861) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 450242475 + ... + 450360208.
It is an arithmetic number, because the mean of its divisors is an integer number (4646209246756).
Almost surely, 253015778140161 is an apocalyptic number.
It is an amenable number.
53015778140161 is a deficient number, since it is larger than the sum of its proper divisors (2738732820911).
53015778140161 is an equidigital number, since it uses as much as digits as its factorization.
53015778140161 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 900602800 (or 900602763 counting only the distinct ones).
The product of its (nonzero) digits is 705600, while the sum is 49.
The spelling of 53015778140161 in words is "fifty-three trillion, fifteen billion, seven hundred seventy-eight million, one hundred forty thousand, one hundred sixty-one".
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