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53015778140861 is a prime number
BaseRepresentation
bin11000000110111101100101…
…00111111010001010111101
320221201020222201210010212102
430003132302213322022331
523422102303201001421
6304431040125114445
714111156255566664
oct1403366247721275
9227636881703772
1053015778140861
111598a9577075a8
125b429909b8a25
13237749c06a3b3
14d13d97bddddb
1561e0de67360b
hex3037b29fa2bd

53015778140861 has 2 divisors, whose sum is σ = 53015778140862. Its totient is φ = 53015778140860.

The previous prime is 53015778140813. The next prime is 53015778140873. The reversal of 53015778140861 is 16804187751035.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 51571500568900 + 1444277571961 = 7181330^2 + 1201781^2 .

It is a cyclic number.

It is not a de Polignac number, because 53015778140861 - 222 = 53015773946557 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 53015778140797 and 53015778140806.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (53015778140881) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26507889070430 + 26507889070431.

It is an arithmetic number, because the mean of its divisors is an integer number (26507889070431).

Almost surely, 253015778140861 is an apocalyptic number.

It is an amenable number.

53015778140861 is a deficient number, since it is larger than the sum of its proper divisors (1).

53015778140861 is an equidigital number, since it uses as much as digits as its factorization.

53015778140861 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5644800, while the sum is 56.

The spelling of 53015778140861 in words is "fifty-three trillion, fifteen billion, seven hundred seventy-eight million, one hundred forty thousand, eight hundred sixty-one".