Base | Representation |
---|---|
bin | 11111100110100… |
… | …011010110000101 |
3 | 1100221122221120212 |
4 | 133212203112011 |
5 | 2041212344231 |
6 | 124340005205 |
7 | 16065424265 |
oct | 3746432605 |
9 | 1327587525 |
10 | 530199941 |
11 | 252314077 |
12 | 129690805 |
13 | 85aca09b |
14 | 505b77a5 |
15 | 3183142b |
hex | 1f9a3585 |
530199941 has 2 divisors, whose sum is σ = 530199942. Its totient is φ = 530199940.
The previous prime is 530199919. The next prime is 530199977. The reversal of 530199941 is 149991035.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 460960900 + 69239041 = 21470^2 + 8321^2 .
It is a cyclic number.
It is not a de Polignac number, because 530199941 - 222 = 526005637 is a prime.
It is a super-2 number, since 2×5301999412 = 562223954872806962, which contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (530199911) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265099970 + 265099971.
It is an arithmetic number, because the mean of its divisors is an integer number (265099971).
Almost surely, 2530199941 is an apocalyptic number.
It is an amenable number.
530199941 is a deficient number, since it is larger than the sum of its proper divisors (1).
530199941 is an equidigital number, since it uses as much as digits as its factorization.
530199941 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 43740, while the sum is 41.
The square root of 530199941 is about 23026.0708980060. The cubic root of 530199941 is about 809.3689852537.
The spelling of 530199941 in words is "five hundred thirty million, one hundred ninety-nine thousand, nine hundred forty-one".
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