Base | Representation |
---|---|
bin | 1111011011100100111… |
… | …00101100100100000101 |
3 | 1212200112121220200111222 |
4 | 13231302130230210011 |
5 | 32141322440240342 |
6 | 1043323201410125 |
7 | 53206610004215 |
oct | 7556234544405 |
9 | 1780477820458 |
10 | 530201102597 |
11 | 194947777921 |
12 | 8690b339945 |
13 | 3acc8094c9a |
14 | 1b93a25a245 |
15 | dbd2232ed2 |
hex | 7b7272c905 |
530201102597 has 2 divisors, whose sum is σ = 530201102598. Its totient is φ = 530201102596.
The previous prime is 530201102549. The next prime is 530201102603. The reversal of 530201102597 is 795201102035.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 353940515041 + 176260587556 = 594929^2 + 419834^2 .
It is a cyclic number.
It is not a de Polignac number, because 530201102597 - 216 = 530201037061 is a prime.
It is a super-2 number, since 2×5302011025972 (a number of 24 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (530201302597) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265100551298 + 265100551299.
It is an arithmetic number, because the mean of its divisors is an integer number (265100551299).
Almost surely, 2530201102597 is an apocalyptic number.
It is an amenable number.
530201102597 is a deficient number, since it is larger than the sum of its proper divisors (1).
530201102597 is an equidigital number, since it uses as much as digits as its factorization.
530201102597 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18900, while the sum is 35.
The spelling of 530201102597 in words is "five hundred thirty billion, two hundred one million, one hundred two thousand, five hundred ninety-seven".
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