53022004033 has 4 divisors (see below), whose sum is σ = 53024965588. Its totient is φ = 53019042480.

The previous prime is 53022003989. The next prime is 53022004093. The reversal of 53022004033 is 33040022035.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 36885891249 + 16136112784 = 192057^2 + 127028^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-53022004033 is a prime.

It is a super-2 number, since 2×53022004033² (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 53022003995 and 53022004013.

It is not an unprimeable number, because it can be changed into a prime (53022004093) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1453758 + ... + 1489783.

It is an arithmetic number, because the mean of its divisors is an integer number (13256241397).

Almost surely, 2^53022004033 is an apocalyptic number.

It is an amenable number.

53022004033 is a deficient number, since it is larger than the sum of its proper divisors (2961555).

53022004033 is a wasteful number, since it uses less digits than its factorization.

53022004033 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2961554.

The product of its (nonzero) digits is 2160, while the sum is 22.

Adding to 53022004033 its reverse (33040022035), we get a palindrome (86062026068).

The spelling of 53022004033 in words is "fifty-three billion, twenty-two million, four thousand, thirty-three".