530220115 has 4 divisors (see below), whose sum is σ = 636264144. Its totient is φ = 424176088.

The previous prime is 530220107. The next prime is 530220149. The reversal of 530220115 is 511022035.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 511022035 = 5 ⋅102204407.

It is a cyclic number.

It is not a de Polignac number, because 530220115 - 2³ = 530220107 is a prime.

It is a super-2 number, since 2×530220115² = 562266740701226450, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 530220092 and 530220101.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 53022007 + ... + 53022016.

It is an arithmetic number, because the mean of its divisors is an integer number (159066036).

Almost surely, 2^530220115 is an apocalyptic number.

530220115 is a deficient number, since it is larger than the sum of its proper divisors (106044029).

530220115 is a wasteful number, since it uses less digits than its factorization.

530220115 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 106044028.

The product of its (nonzero) digits is 300, while the sum is 19.

The square root of 530220115 is about 23026.5089624980. The cubic root of 530220115 is about 809.3792505653.

The spelling of 530220115 in words is "five hundred thirty million, two hundred twenty thousand, one hundred fifteen".